I'm very new to this, and have no idea how bright these are, or how much heat they will produce.
As i said in the past, i have used 5mm leds. The blue ones were 3.2v - 3.8v maximum, and the power supply was from a PC. I just
soldered 4 leds in a series and connected them to the 12v rail on the power supply.. Will i be able to do the same with these?
BTW, power supply is not in a PC, and is a 400w supply with 16a available on 12v rail.
In short, yes you will need a hear sink on these. You can just a strip of aluminum, as long as they are mounted to something using thermally conductive glue.
Each LED is rated for 300-400 mA, at 3.6-4v DC. Heat equals Watts in - Watts out. With LEDs, some of the power (watts) becomes light, but if you ignore that then you have a decent safety margin.
Power = Watts = V*I
We've got 2 voltages and 2 amperages. LEDs tend to need more voltage at higher amps, but we'll do 'em all.
3.6v * 300 mA = 1.08W
3.6v * 400 mA = 1.44W
4v * 300 mA = 1.2W
4v * 400 mA = 1.6W
So I'd expect about 1-1.5W of heat if you're running these things at 300-400 mA.
Voltage: If you have 12.0 VDC between those rails, you'll be running these LEDs at 3.0v each - they're likely to be dim. If you tried 3 LEDs, you'd be running them at 4.0v, which for the LEDs is likely to be screaming hot.
Consider adding a resistor. The way to calculate the value you want is: Pick a drive current (350 mA, say). Make the voltages add up. For 3 LEDs:
V(supply) - V(resistor) - 3* V(LED) = 0
12V - I * R - 3* V(LED) = 0
The voltage of the LED depends on current - I'd guess it's about 3.7v, but that's a WAG.
12V - .35A * R - 3*3.7 = 0
12V - 11.1 = .35*R
.9V = .35R
2.57 ohms = R. Make sure it's rated for at the very minimum 350 mA.
thanks for the responses, and the breakdown!
I just read "each watt of LED power needs about 9 square inches of surface area open to free air for cooling."
As for using aluminum strip, a 3" square piece will work? How thick should it be?
That seems to be extremely conservative. The average surefire 6p has around 17 square inches of aluminum exposed to air, LED's are regularly driven at 5 watts and this is just a single XR-E or XPG, and 10-15 watts seems to be the upper limit. This is also with a relatively poor thermal path compared to an LED directly mounted to a heatsink. The surefire 6p example can be rounded down to an easy 3 square inches per watt, which should be well within the margin of safety, but the heatsinks will get fairly hot to the touch. I suggest using 1/8 inch aluminum, or whatever thickness of U channel you can find close to that. 1/4 is better of course, but 1/8 is easier to cut with tin snips or a hacksaw to make fins. If you have any old computer heatsinks laying around these will work great too.