The field of view (FOV) is affected by the focal length of the lens (3.6mm in your example) and the size of the sensor (the CCD or CMOS element in the camera). For a given sensor, a shorter focal length will have a wider FOV. So, a 50mm lens will have a wider FOV than a 100mm lens.
Now, consider 2 different sensors and the same lens. If sensor A is smaller than Sensor B, then the same lens will give a smaller FOV on camera A than on camera B .
So, you can't compare focal lengths to get FOV without also knowing the sensor size.
The aperture (F2.0 in your example) does not affect FOV. It affects light gathering ability and depth of field (DOF). The aperture is the size of the light-gathering opening. A larger number (higher f-stop) is a smaller opening. The smaller the opening, the less light that gets in (and the darker the picture will be) but the greater the DOF. DOF is the amount of the image that appears to be in focus in front of and behind the actual focal plane.
Large aperture (small f-stop number, e.g. F2) = shallow DOF and bright image
Small aperture (large f-stop number, e.g. F11) = long DOF and dim image
So, the answer is that you need more information. For inexpensive cameras, it may be difficult to find the sensor size.
If you do a search online for "field of view" and "calculator", you will find many web pages that will compute field of view for a given lens focal length. However, most of them will be for film cameras. If you look for an astrophotography site, you will probably find one that allows you to enter the sensor size.
 This is something that digital SLR users worry about - since most sensors are smaller than 35mm film, the field of view of lenses decreases when you go from 35mm film to digital. This is also where the effective 35mm focal lengths that you see for point and shoot cameras come from. For a specific digital camera, a very short lens (a few mm) may be the equivalent of a 50mm lens on a 35mm camera (since the digitals have pretty small sensors).